# Maths item of the month

## Curriculum mapping

A list of Maths Items of the Month categorised by GCSE/A level topics can be seen at: Maths Items of the Month Curriculum mapping.

## Recent Maths Items of the Month

### September 2019

Midpoints of the intersection of a line and a parabola

M is the midpoint of the points of intersection of *y*=*x*^{2} and *y*=2*x*+*c* (as *c* varies). Why does M move as it does?

### July 2019

Sums of three cubes

Both 11 and 12 can be written as the sum of the cubes of three integers:

11 = 3^{3} + (−2)^{3} + (−2)^{3}

12 = 7^{3} + 10^{3} + (−11)^{3}

Which of the numbers from 1-100 can be written as the sum of the cubes of three integers?

### June 2019

MEI Conference 2019 – A couple of taster problems

The 2019 MEI Conference takes place at the University of Bath on 27-29 June. To see details of the conference and the wide variety of sessions on offer visit the conference website: conference.mei.org.uk

The following problems featured in the 2018 Conference sessions Using graphing technology for teaching calculus and Modelling and hypothesis testing with the Normal Distribution.

Which of the following is true:

- e
^{π}<*π*^{e} - e
^{π}=*π*^{e} - e
^{π}>*π*^{e}

Choose either adult men or adult women. How tall are the tallest and shortest that you are likely to meet? Use this to estimate mean and standard deviation.

### May 2019

Calculator Crunch

*Mathematics in Education and Industry* contains the following number of letters in each word:

11, 2, 9, 3, 8.

Using just one pair of brackets, find the difference between the largest and smallest possible values of the expression:

11 × 2 + 9 ÷ 3 − 8

Calculators are allowed!

This is an example of the type of problem that will appear in *Calculator Crunch*: a new fun, free, summer challenge to help Year 6s get ‘calculator-ready’, and provide extra practice for Year 7s. For more details see
mei.org.uk/Primary-KS2-3-Transition.

### April 2019

April fool: 1=−1

Where is the flaw in the following argument?

### March 2019

Regional differences

The parabolas y=*x*^{²}+2*x*−1 and y=*x*^{²}−*x*+1 split the plane into four regions:

What is the maximum number of regions that two parabolas of the form *y*=*ax*^{²}+*bx*+*c* can split the plane into?

What is the maximum number of regions that three parabolas of this form, or four parabolas of this form, can split the plane into?

### February 2019

Thinking equilaterally

Two equilateral triangles share a common vertex. Show that the lengths marked *a* and *b* are equal for any such arrangement.

Investigate the ratio *a*:*b* for other pairs of regular polygons.

### January 2019

Happy 2019

Some problems about the number 2019:

- The number 2019, its double 4038, and its triple 6057 contain all 10 digits. What is the next number with this property?
- The number 2019 can be written as the sum of the first
*n*perfect powers (integers of the form*a*where^{m}*a*>0 and*m*≥2). What is the value of*n*? - 2019 is the smallest number that can be written as the sum of the squares of 3 primes,
*p*^{2}+*q*^{2}+*r*^{2}, in*n*different ways (where the order doesn't matter). What is the value of*n*?

### December 2018

Christmas trees

A Christmas tree is made by stacking successively smaller cones. The largest cone has a base of radius 1 unit and a height of 2 units. Each smaller cone has a radius 3/4 of the previous cone and a height 3/4 of the previous cone. Its base overlaps the previous cone, sitting at a height 3/4 of the way up the previous cone.

What are the dimensions of the smallest cone, by volume, that will contain the whole tree for any number of cones?

### November 2018

Terms of engagement

Two arithmetic sequences: *t*_{1}, *t*_{2}, *t*_{3}, ... and *u*_{1}, *u*_{2}, *u*_{3}, ... are multiplied term-by-term to form the terms of a new sequence:

*t*_{1}*u*_{1}, *t*_{2}*u*_{2}, *t*_{3}*u*_{3}, ...

The first three terms of the new sequence are 360, 756 and 1260. What is the fourth term?

Given that all the terms of the sequences are positive integers what could the original sequences be?

### October 2018

Ritangle competition

Ritangle is a competition for teams of students of A level Mathematics, the International Baccalaureate and Scottish Highers: integralmaths.org/ritangle. The first five questions will be released on 1st, 8th, 15th, 22nd, 29th October 2018. Correct answers to these questions release a clue for the final question.

**Question 1**

How many 8 digit numbers are there that are both:

a) divisible by 18

and

b) such that every digit is a 1 or a 2 or a 3?

**Question 2**

In this question *a* > 0.

The line *y* = 3*ax* and the curve *y* = *x*^{2} + 2*a*^{2} enclose an area of size *a*.

What is the value of *a*?

**Question 3**

Let f(*x*) = 10*x*^{2} + 100*x* + 10.

Suppose f(*a*) = *b* and f(*b*) = *a*.

Given that *a* ≠ *b*, what is f(*a* + *b*)?

**Question 4**

In this question *a* and *b* are positive. A quadrilateral is formed by the points A, B, C and D where A is (*a*,0), B is (0,*b*), C is (-1/*b*,0) and D is (0,-1/*a*). ABCD is always a trapezium.

If *a*=11 what value of *b* minimises the area of trapezium ABCD?

**Question 5**

In this question angles are in radians. An infinite sequence *x*_{0}, *x*_{1}, *x*_{2}, *x*_{3}, ... is defined as follows:

*x*_{0}=1, *x*_{2n+1}=cos(*x*_{2n}), *x*_{2n+2}=arctan(*x*_{2n+1}) for all integers *n*≥=0.

Find the limit to which the sequence *y*_{n} = *x*_{2n+1} − *x*_{2n+2} (*n*≥=0) converges.

**Please don’t share answers outside your team, others are having
fun finding them!**